Consider the paraboloid z=f(x,y)= 4+x^2+3y^2 . Beginning at (3,4,61) on the surface, find the path in the xy-plane that points in the direction of steepest descent on the surface.

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Take the gradient?

Gradient = <2x, 6y>
Your vector: 6i + 24j
@AccessDenied help! I thought I remembered all of this :-(

When they say "path" are they looking for the equation of the line or do they want the vector?

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