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you forgot to put the rest of the equation
The equation is on the second line, but here it is again: (sinx-1)(2sin^2 x-5sinx+2)
but it has to equal something to solve it
Hmm...It's not set to equal anything... but maybe equals x?
@dpalnc...If i factor it will I have to solve more after that in order to get to the answer?
@missfitz5172 , forget that... I misread "interval" as "integrate".... hehe :)
do you want the zeros of this graph? i.e., where the graph crosses the x-axis?
@dpalnc, I'm looking for the solutions. I think that if this were graphed, that the zeroes would be the same as the solutions, so I think so...
the problem does not state an equation to solve. is this the equation: (sinx-1)(2sin^2 x-5sinx+2) = 0
@dpaInc, yes that is the equation
if it is, then factoring will definitely help.
factor this part of the expression: (2sin^2 x-5sinx+2)
@dpaInc , (2sin^2 x-5sinx+2) factored to (2sinx-1)(sinx-2) so does that mean that all together I have (sinx-1)(2sinx-1)(sinx-2) ?
notice that last factor (sinx -2) will not help any...
ok, now my answer has to be in a form on the unit circle...how can i translate these factored groups to something in a fraction with pi?
can you explain why the (sinx-2) doesn't help?
you'll need to set each factor to 0: sinx - 1 = 0 and 2sinx - 1 = 0 let's work on the first one...|dw:1333235792196:dw|
ok, lemme explain about that last factor, sinx - 2. when you solve sinx -2 = 0, you'll get: sinx = 2. look at the unit circle. what angle can you take the sine of to get 2?
sinx-1=0 equals x=pi/2 Could it be either pi/6, pi/4, or pi/3? (about what sine to get 2)
notice that sine can never be bigger than 1 or smaller than -1. that's why sinx = 2 does not have a solution.
ooohhh...i apologize, i'm not good at math haha. Ok, so sinx-1=0 equals x=pi/2
that's ok... i'm not good either!!!
but the answer about that first factor is yes, x=pi/2 now how about that second factor...
2sinx - 1 = 0 factors to be x = pi/6
is that it? there's 1 more you forgot..
the (sin x -2)?
Ok... so i'm not sure which factor that is, but is it 5pi/6?
that should be it then since sinx - 2 doesnot have a solution...
ok, so then my answer should be pi/2, pi/6, and 5pi/6...
yep, in the interval 0 to 2pi....
wow. thank you so much for your help!! really really, it means a lot (: thanks again (:
way to stick with it... and good job. :)
i really appreciate that you explained everything too (: and thanks!