anonymous
  • anonymous
Trigonometry. Rationalize the numerator. Assume that all radicands are nonnegative. 3+sin y/3-sin y (all under one square root)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
thinking of multiplying both numerator and denominator by 3+siny? then change sin^2 to 1-cos^2, dunno
anonymous
  • anonymous
ohh sqrt() did not see that, let me write it down!
anonymous
  • anonymous
anyone helping?

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anonymous
  • anonymous
trying to find some paper grr
phi
  • phi
Is this the problem \[ \sqrt{\frac{3+sin(y)}{3-sin(y))} } \]
anonymous
  • anonymous
yes that's how it looks
phi
  • phi
Rationalize the numerator (normally people rationalize the denominator) multiply top and bottom by sqrt(3+sin(y))
anonymous
  • anonymous
doing that, but i get to 3+siny/sqrt(cos^2x+8)
anonymous
  • anonymous
hmmm, think u need to do it like sqrt\[((\sqrt(3+sinx)/\sqrt(3-sinx))*(\sqrt(3-sinx)/\sqrt(3-sinx))\]
anonymous
  • anonymous
so then is it sqrt() 9+sin^2/9-sin^2y ???
anonymous
  • anonymous
so u get to \[\sqrt(9-\sin^2 x)/(3-\sin x)\]
anonymous
  • anonymous
that is it! this is the answer, no square root at the denominator

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