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laura80

  • 2 years ago

use an inequality to solve: 1 side of a rectangle is 5 and the other is x,, find the possible values of x if the area is at least 60...... I found out what x would be it would be 25 but idk how to do the inequality im not to sure anyone

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  1. Koran90
    • 2 years ago
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    I can help

  2. Koran90
    • 2 years ago
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    The inequality is simply the x on its own multipled by the indices

  3. Koran90
    • 2 years ago
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    |dw:1333247460431:dw|

  4. Dockworker
    • 2 years ago
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    first, where'd you get 25 from?

  5. Koran90
    • 2 years ago
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    Multiplying an indices gets 25 from the number bank

  6. Dockworker
    • 2 years ago
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    Koran, you're not being original or funny. I see at least 5 people do what you are doing whenever I come on here

  7. laura80
    • 2 years ago
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    well to get the area it is l^2+w^2 so it would be 5+5+x+x=60 so it would be 10+2x=60

  8. Koran90
    • 2 years ago
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    Its a hypothetical model to inequalities devised by the indices I am not being funny. I tutor higher mathemtatics

  9. Dockworker
    • 2 years ago
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    5+5+x+x would give you the perimeter, not the area

  10. laura80
    • 2 years ago
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    oh crap

  11. SUROJ
    • 2 years ago
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    area is at least 60 means lenght*bredth >=60 5*x>=60 x>=12

  12. Dockworker
    • 2 years ago
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    area=length*width perimeter=2(length+width)

  13. Koran90
    • 2 years ago
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    no perimenter*indices*diagnonals(length=width0

  14. SUROJ
    • 2 years ago
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    so if you take value of x equal or greater than 12 then area would be at least 60 or more than 60 but not less than 60

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