Here's the question you clicked on:
laura80
use an inequality to solve: 1 side of a rectangle is 5 and the other is x,, find the possible values of x if the area is at least 60...... I found out what x would be it would be 25 but idk how to do the inequality im not to sure anyone
The inequality is simply the x on its own multipled by the indices
first, where'd you get 25 from?
Multiplying an indices gets 25 from the number bank
Koran, you're not being original or funny. I see at least 5 people do what you are doing whenever I come on here
well to get the area it is l^2+w^2 so it would be 5+5+x+x=60 so it would be 10+2x=60
Its a hypothetical model to inequalities devised by the indices I am not being funny. I tutor higher mathemtatics
5+5+x+x would give you the perimeter, not the area
area is at least 60 means lenght*bredth >=60 5*x>=60 x>=12
area=length*width perimeter=2(length+width)
no perimenter*indices*diagnonals(length=width0
so if you take value of x equal or greater than 12 then area would be at least 60 or more than 60 but not less than 60