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laura80
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use an inequality to solve: 1 side of a rectangle is 5 and the other is x,, find the possible values of x if the area is at least 60...... I found out what x would be it would be 25 but idk how to do the inequality im not to sure anyone
 2 years ago
 2 years ago
laura80 Group Title
use an inequality to solve: 1 side of a rectangle is 5 and the other is x,, find the possible values of x if the area is at least 60...... I found out what x would be it would be 25 but idk how to do the inequality im not to sure anyone
 2 years ago
 2 years ago

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Koran90 Group TitleBest ResponseYou've already chosen the best response.0
The inequality is simply the x on its own multipled by the indices
 2 years ago

Koran90 Group TitleBest ResponseYou've already chosen the best response.0
dw:1333247460431:dw
 2 years ago

Dockworker Group TitleBest ResponseYou've already chosen the best response.0
first, where'd you get 25 from?
 2 years ago

Koran90 Group TitleBest ResponseYou've already chosen the best response.0
Multiplying an indices gets 25 from the number bank
 2 years ago

Dockworker Group TitleBest ResponseYou've already chosen the best response.0
Koran, you're not being original or funny. I see at least 5 people do what you are doing whenever I come on here
 2 years ago

laura80 Group TitleBest ResponseYou've already chosen the best response.0
well to get the area it is l^2+w^2 so it would be 5+5+x+x=60 so it would be 10+2x=60
 2 years ago

Koran90 Group TitleBest ResponseYou've already chosen the best response.0
Its a hypothetical model to inequalities devised by the indices I am not being funny. I tutor higher mathemtatics
 2 years ago

Dockworker Group TitleBest ResponseYou've already chosen the best response.0
5+5+x+x would give you the perimeter, not the area
 2 years ago

SUROJ Group TitleBest ResponseYou've already chosen the best response.2
area is at least 60 means lenght*bredth >=60 5*x>=60 x>=12
 2 years ago

Dockworker Group TitleBest ResponseYou've already chosen the best response.0
area=length*width perimeter=2(length+width)
 2 years ago

Koran90 Group TitleBest ResponseYou've already chosen the best response.0
no perimenter*indices*diagnonals(length=width0
 2 years ago

SUROJ Group TitleBest ResponseYou've already chosen the best response.2
so if you take value of x equal or greater than 12 then area would be at least 60 or more than 60 but not less than 60
 2 years ago
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