anonymous
  • anonymous
When using nCr, how do you solve (1/3) C 1 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dumbcow
  • dumbcow
i dont think you can because , one factorials are only defined for positive integers, and two, 1 > 1/3 and n mustr be greater than r
anonymous
  • anonymous
I thought there was another formula for it. Because my teacher told me (1/3)C2 was (1/3((1/3)-1)/2!)
dumbcow
  • dumbcow
oh ok, i have never seen fractions used with combinations i won't work on a calculator

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dumbcow
  • dumbcow
it*
Zarkon
  • Zarkon
(1/3) C 1 =1/3
anonymous
  • anonymous
I'm pretty sure it's negative 1/3. But if it's like that, how would you do (1/2) C 2?
Zarkon
  • Zarkon
no it's 1/3 but (1/2) C 2=-1/8
anonymous
  • anonymous
Could you write up the equation for me please?
Zarkon
  • Zarkon
\[\binom \alpha k = \frac{\alpha(\alpha-1)(\alpha-2)\cdots(\alpha-k+1)}{k(k-1)(k-2)\cdots 1}\]
Zarkon
  • Zarkon
\[_\alpha C_k=\binom \alpha k\]
anonymous
  • anonymous
I understand the bottom part as a factorial, but how would you do the top part?
Zarkon
  • Zarkon
\[_{1/2}C_2=\frac{\frac{1}{2}\left(\frac{1}{2}-1\right)}{2(2-1)}=\frac{\frac{1}{2}\cdot\frac{-1}{2}}{2}=-\frac{1}{8}\]
anonymous
  • anonymous
how do you how many times you repeat the "(x-1)"? You said it was α(α−1)(α−2).... but you only repeated 2 times above.
Zarkon
  • Zarkon
because k=2

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