Linear Inequalities: Sally intends to give 12 good friends toys. Her friends can either have a teddy bear or a toy car. A teddy bear cost $1.50 while a toy car cost $1.20. If she only has $16 to spend on the gifts, what is the max n.o of teddy bear her friend can have. Solve in linear inequalities.:D
Let x be the max n.o of teddy bear
This is what i have done so far
1.50x-1.2(12-x)<16
2.7x<30.4

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b + c = 12 toys
1.5b + 1.2 c <= $16
-> 1.2b + 1.2c = 14.4
=> b = 1.6 / .3 = 5.3 Max is 5 bears

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