anonymous
  • anonymous
Suppose all the dimensions of a cube are multiplied by 4. a. what happens to its surface area? b. what happens to its volume?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1333253338779:dw| so, SA = 6(6x)^2 = 6*36x^2 = 36*6x^2 the surface area is 36 times the original for volume, V = (6x)^3 = 6*6*6*x^3 = 216*x^3 the volume is 216 times the original volume.
anonymous
  • anonymous
|dw:1333290594964:dw| wouldn't you do 4 * 4 * 4? since it's multiplied by 4..?
anonymous
  • anonymous
so the side of this new cube will be 4s where s is the side of the previous cube. the surface area and volume of the previous one will be SA=6s^2 V=s^3 now if we multiply the dimension(side of the cube in this case) by four then, SA=6(4s)^2 V=(4s)^3 SA=96s^2 V=64s^3 so the SA of the cube if its dimension is multiplied by 4 will be 16 times the size of its previous SA and its V will be 64 times the size of its previous V

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anonymous
  • anonymous
Ah ok.. so do you know how the dpalnc got 36 and 216 times bigger? Your answer makes sense...
phi
  • phi
re: dpal sometimes you have a brain freeze. Somehow got 6 on his mind (probably thinking of the surface area formula: 6 sides) and used 6 rather than 4 for the multiple. btw, it is generally the case that if you have multiply the sides by x, the surface area of an object grows by x^2 and its volume by x^3
anonymous
  • anonymous
thanks!
anonymous
  • anonymous
in my answer, I do not have to have the letter s .. like for V it is 64s.. can I just say that it is 64 times bigger?
anonymous
  • anonymous
thanks!

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