anonymous
  • anonymous
How can I name a point on the terminal side of 240 degrees?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
think of your unit circle. can you name a point on the terminal side of 60º?
anonymous
  • anonymous
the only difference between the 2 is that the x and y-coordinates will be negative if the terminal side lies in the 3rd quadrant
anonymous
  • anonymous
|dw:1333253528625:dw|

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anonymous
  • anonymous
think of a 30-60-90 triangle with a hypotenuse of 1
anonymous
  • anonymous
So between possible choices of either (-1, -(square root 3)) and (-(square root 3), -3), how do I determine which is the correct choice? They both seem plausible to me.
anonymous
  • anonymous
those are both points on the same terminal side because their tangents are equal
anonymous
  • anonymous
I am under the impression that there is only one correct answer choice, though. There were three other possibilities I tossed out because the above points are the only ones that are negative for both x and y.
anonymous
  • anonymous
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anonymous
  • anonymous
seems to me that both points would be on the terminal side
anonymous
  • anonymous
did somewhere further up it mention that it has to be a point on the unit circle?
anonymous
  • anonymous
No, that's the entire question. I am trying to figure out what it means. Would (-(sqr rt 3), -3) be on the same side since they are further apart than (-1,-(sqr rt 3)?
anonymous
  • anonymous
-3/-sqrt(3)=-sqrt(3)/-1=sqrt(3)
anonymous
  • anonymous
(-(sqr rt 3), -3) is (-1.73, -3), while (-1, -(sqr rt 3)) is about (-1, -1.73)? Second one seems more plausible, right?
anonymous
  • anonymous
neither seems more plausible, both points lie on the ray that is 240º counter-clockwise from the positive x-axis
anonymous
  • anonymous
Hmm... bad question then I guess. Ah well, I'll take a stab at one or the other thanks.
anonymous
  • anonymous
yw

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