anonymous
  • anonymous
7 log base 9 (x+8)=7
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
divide by 7 to get log9 (x+8) = 1 change to exponential form 9^1 = x+8 now solve for x....
anonymous
  • anonymous
When b raised to the power of y is equal x: b y = x Then base b logarithm of x is equal to y: logb(x) = y For example when: 24 = 16 Then log2(16) = 4 Logarithm as inverse function of exponential function The logarithmic function, y = logb(x) is the inverse function of the exponential function, x = by So if we calculate the exponential function of the logarithm of x (x>0), f (f -1(x)) = blogb(x) = x Or if we calculate the logarithm of the exponential function of x, f -1(f (x)) = logb(bx) = x Natural logarithm (ln) Natural logarithm is a logarithm to the base e: ln(x) = loge(x) When e constant is the number:
anonymous
  • anonymous
how did you type all that that fast?

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anonymous
  • anonymous
my typing is really very fast
anonymous
  • anonymous
i see....
anonymous
  • anonymous
thanks
anonymous
  • anonymous
yw
lgbasallote
  • lgbasallote
dpalnc is funny =))))

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