anonymous
  • anonymous
log base 2 (a^2-6a) = log base 2 (10+3a)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1333255112352:dw| can you take it from here?
anonymous
  • anonymous
hint: log2(1) = 0 log2(2) = 1 log2(3) = 1.584962500721156 log2(4) = 2 log2(5) = 2.321928094887362 log2(6) = 2.584962500721156 log2(7) = 2.807354922057604 log2(8) = 3 log2(9) = 3.169925001442312 log2(10) = 3.321928094887362 Note that log2(x) is defined for any x greater than zero. If you have a calculator than computes the natural logarithm (often denoted ln), then you can calculate log2(x) = ln(x)/ln(2). The same thing works with log base 10, i.e. log2(x) = log10(x)/log10(2).
anonymous
  • anonymous
dpalnc_ I thought that the log base 2 cancels out and then the equation is: a^2-6a= 10+3a? Then you take it from there.

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anonymous
  • anonymous
silly me... yeah, i should've done that.... but the equation will still be the same... I like to do it the long way... NOT! :)
anonymous
  • anonymous
can you take it from there then?
anonymous
  • anonymous
the answer is -1, 10...but I can't figure out how to get there
anonymous
  • anonymous
yes, a = 10 , a = -1
anonymous
  • anonymous
it's probably the quadratic equation then...
anonymous
  • anonymous
Never mind!!! I figured it out...thanks!!!
anonymous
  • anonymous
no, it's factoring
anonymous
  • anonymous
|dw:1333255705473:dw| factor that left side...
anonymous
  • anonymous
a^2-9a+10=0
anonymous
  • anonymous
yeah
anonymous
  • anonymous
|dw:1333255799847:dw|
anonymous
  • anonymous
didn't read the above post that you figured it out already...
anonymous
  • anonymous
your right! I was wrong with the +10...it should have been -10

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