anonymous
  • anonymous
A flask with 2.50 L of gas is under 3.00 atm of pressure. the gas is heated and the volume increases to 5.00 L. what is work done by the gas? (in J)
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AravindG
  • AravindG
is temp constant??
anonymous
  • anonymous
i think so , it says nothing about temp
AravindG
  • AravindG
wel i suppose then it is isothermal expansion

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More answers

AravindG
  • AravindG
use the formula for work done in osthermal expansion to get the result
anonymous
  • anonymous
is it, deltaH=deltaE + deltanRT
anonymous
  • anonymous
or deltaE = q+w?
AravindG
  • AravindG
oh not that
AravindG
  • AravindG
use the formula :below http://en.wikipedia.org/wiki/Isothermal_process
AravindG
  • AravindG
under calculation of work done
anonymous
  • anonymous
w=pdv?
AravindG
  • AravindG
nooo!!
AravindG
  • AravindG
look under calculation of work done
anonymous
  • anonymous
i dont have mol
AravindG
  • AravindG
oh srry then i suppose u jst need to do this: work=PdeltaV
AravindG
  • AravindG
u get that?
anonymous
  • anonymous
can u solve it and show me
AravindG
  • AravindG
srry i am a bit busy
JFraser
  • JFraser
work done at constant temp is \[w = -P \Delta V\]
anonymous
  • anonymous
how do i use this equation
anonymous
  • anonymous
Just plug the numbers in. \[w=-3.00atm(5.00L-2.50L)\]
anonymous
  • anonymous
the answer is suppose to be 759.8J , but i think ur right and the worksheet may be wrong
anonymous
  • anonymous
well right now it's in units of liters times atms. We convert that using the equation\[{101.31Joules \over L* atm} \times 7.5 L* atm = 759.8J\] the 101.31 number you should have memorized.
anonymous
  • anonymous
Always assume a work sheet is right. 99% of the time they are.
anonymous
  • anonymous
lol thank you so much!
AravindG
  • AravindG
hmm..... isnt that what i just said :P
anonymous
  • anonymous
SO SIMPLE QUESTION
anonymous
  • anonymous
WORK OF EXPANSION=pRESSURE*CHANGE IN VOLUME NOW ACCORDING TO UR QUESTION W=P DELTA V W=3(5-2.50) W=3*2.5 W=7.5

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