• anonymous
Two atoms have the electron configurations 1s2 2s2 sp6 and 1s2 2s2 2p6 3s1. The first ionization energy of one is 2080 kJ/mol and that of the other is 496 kJ/mol Match each ionization energy with one of the given electron configurations. Justify your choice. The answer is 1s2 2s2 2p6: 2080 k/mol I can't figure out how to get this answer. Please help!! :(
  • Stacey Warren - Expert
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  • chestercat
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  • anonymous
look p has 3 orbitals which can accomodate a max of 6 electrons . Hence when you have a fully filled outer shell (here 2p6) the molecule tends to become much more stable and it is difficult to remove electrons from a stable configuration... so a higher energy has to be given to the system to remove the electron, hence its higher I.E. value. the other one having half-filled configuration, needs less energy to remove an electron from the outer most shell, hence a comparatively lower I.E.

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