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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
this is d/dx (5)  d/dx (x5) derivative of 5 = 0..and the derivative of x5 = 1 so.. 01 = 1
 2 years ago

ChrisV Group TitleBest ResponseYou've already chosen the best response.0
wouldnt you have a +/ value since its absolute value?
 2 years ago

CoCoTsoi Group TitleBest ResponseYou've already chosen the best response.4
As there is a absolute value, we have to consider two cases. f(x)=5x5 case i), for x>5 f(x) = 5(x5) = 5x+5 =10x f'(x) =1 case ii) for x<=5, f(x)= 5((x5) ) =5+(x5) =x f'(x)=1
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
oh wait..that was absolute value?? so sorry! thought they were parentheses
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
my eyes are failing baaad
 2 years ago

Rohangrr Group TitleBest ResponseYou've already chosen the best response.0
If the problem is 1/(x  5), then, by the power rule, the derivative is: 1/(x  5)^2 The slope, m, of the tangent line is the derivative evaluated at the xcoordinate of the point. Plug in 4 for x: m = 1/(4  5)^2 = 1/81 Then solving y = mx + b for the yintercept after plugging in the point: 1/9 = 4/81 + b b = 1/9  4/81 = 13/81 Tangent line equation is: y = 1/81*x  13/81 Hope this helps.
 2 years ago

brinethery Group TitleBest ResponseYou've already chosen the best response.0
1/(x5) = (x5)^1. Then you use the chain rule to take the derivative.
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
dw:1333266207662:dw you can treat it as a piecewise function. so if you want the derivative, f'(x) will be something different depending on the x you look at...
 2 years ago
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