anonymous
  • anonymous
I hope it doesn't seem like I'm asking a ton of questions, but I'm finishing up my geometry course and I have just a few more questions until I'm completely done! Help with this question? Picture attached! :)
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
3y+4=11y 8y=4, y=1/2
anonymous
  • anonymous
hey take help from these Let AB and AC be two tangent lines from a point A outside a given circle. Show? that AB is congruent to AC. How do I write the proof? Please help! http://blog.csharphelper.com/2010/08/20/… Go to the web site above to see a picture of this problem. A line which is tangent to a circle at a specific point is perpendicular to a line from the center of the circle to the same point. The line from the center of the circle to the same point is a radius. Lines AB and AC are the two tangent lines from a point A outside a given circle. Let O = center point of the circle. Lines OB and OC are the radius lines. The 2 tangent lines, AB and AC, and the 2 radius lines, OB and OC, form a quadrilateral. Angle ABO and angle ACO are right angles. A line from the point A to point O divides the quadrilateral into 2 right triangles, ABO and ACO. Line AO is the hypotenuse of both right triangles. AB^2 + OB^2 = AO^2 AB^2 = AO^2 – OB^1 AC^2 + OC^2 = AO^2 AC^2 = AO^2 – OC^2 The radius lines, OB and OC, are equal length So, OB^2 = OC^2. So, AB = AC

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anonymous
  • anonymous
the angle E and C are the same, so DE//AC. Therefore DBE and ABC are similar triangles. Let EC=x, then 32/48=28/28+x then x=14, so BC=42

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