anonymous
  • anonymous
The equation kx^2 + 2kx - 4 + k = 0 has no real roots. Find the range of values of k.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
For exactly two real roots, k > sqrt(8). The equation to be solved is x = (-k +- sqrt(k^2 - 4*2))/2 2 real roots occur when the discriminant (sqrt(k^2 - 4*2)) is larger than 0, thus k^2 > 8, so, k > sqrt(8).
Callisto
  • Callisto
Since it has no real roots Δ<0 (b^2 -4ac) <0 Put b = 2k, a= k, and c = -4+k into the inequality (2k)^2 - 4(k)(-4+k) <0 4k^2 + 16k - 4K^2 <0 Can you solve it from here?
anonymous
  • anonymous
Thank you, guys! (: Yes, thanks, Callisto!

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anonymous
  • anonymous
an what about me!!
Callisto
  • Callisto
Welcome, glad to help!
anonymous
  • anonymous
Hahaha, sorry. Thanks, Eric! (:

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