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calyne

  • 4 years ago

Find dy/dx by implicit differentiation: 4 cos x sin y = 1

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  1. experimentX
    • 4 years ago
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    - 4 sin x sin y + 4 cos x cos y dy/dx = 0 => dy/dx = sin x sin y/ cos x cos y = tan x tan y

  2. lalaly
    • 4 years ago
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    use the product rule,, \[-4sinxsiny+4cosxcosy \frac{dy}{dx}=0\]\[\frac{dy}{dx}=\frac{4sinxsiny}{4cosxcosy}=tanxtany\]

  3. .Sam.
    • 4 years ago
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    4cosxsiny=1 differentiate, 4[(cosx)(cosy)(y')+(siny)(-sinx)]=0 4(cosx)(cosy)(y')=4sinxsiny (y')=4sinxsiny /4(cosx)(cosy)

  4. calyne
    • 4 years ago
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    thanks guyz

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