anonymous
  • anonymous
A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How far must the student be pushed, starting from rest, so that her final kinetic energy is 352 J?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ujjwal
  • ujjwal
we have F=ma, i.e. a=F/m according to info given in question a=45/m.....(1) again, (1/2)mv^2 = 352 or, v^2= 352 * 2/m.....(2) Also we have v^2=2as.... (3) (starting from rest) solving (1), (2) and (3) we get s=7.82 m hence the student must be pushed 7.82 m..
anonymous
  • anonymous
What does "a" stand for?
ujjwal
  • ujjwal
acceleration

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anonymous
  • anonymous
alright Thank You! :D
ujjwal
  • ujjwal
you are most welcome.. :)
anonymous
  • anonymous
Another method: By using principal of conservation of energy: workdone=change in kinetic energy F*d=(K.E)final-0; d=(K.E)final/F=352/45=7.82m
anonymous
  • anonymous
Thank You!

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