anonymous
  • anonymous
...
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
mathteacher1729
  • mathteacher1729
This is: 1) Identical to the question you asked previously. 2) Looks like it's taken directly from a graded assignment.
anonymous
  • anonymous
guess it was not clear the first time, do you have a specific question?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
your job now is only to evaluate \[32(\cos(\frac{\pi}{2}+i\sin(\frac{\pi}{2}))\] which comes down to evaluating \[\cos(\frac{\pi}{2})\] and \[\sin(\frac{\pi}{2})\] and multipling the result by 32
anonymous
  • anonymous
i got it the first time, the problem is that the website where im doing the homework keeps telling me that the answer is wrong
anonymous
  • anonymous
well cosine of \(\frac{\pi}{2}\)=0 and \(\sin(\frac{\pi}{2})=1\) so you should get 32i
anonymous
  • anonymous
wait so 32 is the imaginary?
anonymous
  • anonymous
it is \[32(0+i)=32i\]
anonymous
  • anonymous
and 0.279 is the real number?
anonymous
  • anonymous
there is no real part
anonymous
  • anonymous
i am not sure where you are getting the numbers from \[\cos(\frac{\pi}{2})=0,\sin(\frac{\pi}{2})=1\]
anonymous
  • anonymous
you have \[2^5(\cos(\frac{\pi}{2})+i\sin(\frac{\pi}{2}))=32(0+i)=32i\]
anonymous
  • anonymous
if you are using a calculator to evaluate (looks like it) make sure to put it in "radian" mode and then use exact (not decimal) numbers for your input
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=cos%28pi%2F2%29
anonymous
  • anonymous
thats why i was getting it wrong
anonymous
  • anonymous
when i have a 30' in an equation , what does that mean?radians?

Looking for something else?

Not the answer you are looking for? Search for more explanations.