anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jhonyy9
  • jhonyy9
3rd
wasiqss
  • wasiqss
linear
hoblos
  • hoblos
a straight line corresponds to a linear function

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anonymous
  • anonymous
whoops fail posted wrong file -____-
anonymous
  • anonymous
i ment to post this
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jhonyy9
  • jhonyy9
i think just the last one can being
anonymous
  • anonymous
thats what i was thinking but im kinda effy
anonymous
  • anonymous
It's definitely the 3rd one.
anonymous
  • anonymous
how puddle?
jhonyy9
  • jhonyy9
why ? - so if you check these digrammes so you can see that from this functions just the last one can result negativ roots - so hence this guarantee that this is the right answer
jhonyy9
  • jhonyy9
hope that you can understanding those my words
jhonyy9
  • jhonyy9
ok ?
anonymous
  • anonymous
i can jhony no worrys thanks for the help
jhonyy9
  • jhonyy9
ok good luck bye
anonymous
  • anonymous
Functions in the form1/x+a form asymptotes which is what you have on your graph.
anonymous
  • anonymous
If you would like visual proof. Type y=-1/(x+2) into google. They have a new graphing system.
anonymous
  • anonymous
alright
anonymous
  • anonymous
If you subbed in -2 into the function to form the graph you'd end up with -1/0, which is undefined. This is what creates the two lines. For example. Take the simple function 1/x. Sub in values for x between -2 and 2. This gives us the points (-2,-1/2), (-1,-1), (1,1) and (2,1/2). Plotting these points gives us: |dw:1333301666652:dw|

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