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There are no other restrictions.
always nice to have a picture of the area we are looking at|dw:1333301688461:dw|
...something like that ;)
around the x axis I recommend disk method are you familiar with it?
It is not bounded by y=0...
Yes, I am familiar with disk, washer, and cyndrilical shells.
then it is infinite, hooray!
But only to a certain extent.
That's a good thing?
how do you figure? if it is not bounded below by y= something the area is infinite, which means any solid you can get from revolving around a line is infinite, so I'm going to say they mean the positive portion of y.
Huh? So when revolved around the y axis, the answer is infinity?
of course if the area is infinite how could the volume obtained by spinning it around something be finite?
Then what about part a: the x-axis?
Mind you, this is an even question so I don't have the answers.
if this is the exact wording of the question it is poor it says the area "under the function" but that could be either in the x direction or y direction, so that is lame... I'm pretty sure they mean this region|dw:1333302430100:dw|
but it's not bounded by y=0 like I said. It wasn't in the wording...
if it is not this, I have no idea what they mean technically the area \(under\) the graph is infinite if it is this, use disk method to revolve about x
...and use shell method to revolve about y
I'm quite certain they want you to bound it by y=0, and the challenge to the problem, I believe, is the partial fractions integral that results
Good observation. This question is actually in the section of partial fractions.
so do you think you can do it now?
Still working on finding the constants. Quadratics are a pain in the back..
If I use the shell method, what's the radius?
Heck, screw the radius, what are the limits?