precal
  • precal
Give the location of the vertical asymptote(s) if they exist, and state the functions domain. I believe the textbook's solution may be incorrect
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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precal
  • precal
\[h(x)=\frac{x^2-1}{2x^2+3x-5}\]
anonymous
  • anonymous
\[h(x)=\frac{(x-1)(x+1)}{(x-1)(2x+5)}\] it has 1 vertical asymptote at x=-5/2
precal
  • precal
I factored them and got \[h(x)= \frac{(x+1)(x-1)}{(x+\frac{5}{2})(x-1)}\]

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precal
  • precal
I wrote that the same v.a value but my book states x=1 also. I believe that is a hole. For the domain |dw:1333303949399:dw|
anonymous
  • anonymous
right, x=1 is a removable discontinuity because x-1 is also a factor of the numerator
precal
  • precal
Thanks, I believe my book is incorrect. I just wanted to make sure, I was on track. :)

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