anonymous
  • anonymous
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta)....Help Dx
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
In order to find cot(theta) you need to know \[\cot(\theta)\] in addition to \[\sin(\theta)\].. correct? Since your \[\cot(\theta) = \cos(\theta)/\sin(\theta)\] ....
anonymous
  • anonymous
so far you have \[\sin(\theta)=4/5\], and you can use that to find that \[\cos(\theta)=3/5\] Once you have that you can just plug in to find \[\cot(\theta)\]
anonymous
  • anonymous
so what would \[\cot(\theta) = \] ?

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anonymous
  • anonymous
mistake on my first post.. I meant to say "cos in addition to sin" ... but does this all make sense to you?
anonymous
  • anonymous
-3/4 ?
anonymous
  • anonymous
yeah, actually you would have a (-3/5) for the cos .. you're right.. and then you would get -3/4 for cot
anonymous
  • anonymous
since we're in the second quadrant
anonymous
  • anonymous
Ok thanks :)

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