anonymous
  • anonymous
Questions 5 and 6: Calculate the length of the unknown side for the given right triangle.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1333309786130:dw| modify my triangle ... and write the givens...
anonymous
  • anonymous
If you already know two sides then you can use Pythagoras Theorem: (Side1)^2 + (Side2)^2 equals (Hypotenuse)^2
anonymous
  • anonymous
Yes... \[\Large a^2+b^2=c^2\]

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anonymous
  • anonymous
|dw:1333309644487:dw| 5. Calculate the length of the unknown side for the given right triangle. a. 1 b. squareroot 15 c. 15 d. squareroot 115
anonymous
  • anonymous
|dw:1333310559821:dw| 6. Calculate the length of the unknown side for the given triangle. a. 6 b.6 squareroot 5 c. 6 squareroot 13 d. 30
anonymous
  • anonymous
b. Using Theorem of Pythagoras we have 8^2 = 7^2 + x^2. So, 64 = 49 + x^2 64-49 = x^2 15 = x^2 \[\sqrt{15}\] = x
anonymous
  • anonymous
\[\Large 8^2-7^2=c^2\Longrightarrow 64-49=c^2 \longrightarrow c^2=15\] \[\LARGE c=\sqrt{15}\]
anonymous
  • anonymous
In the first one 8 is the longest side, or the hypotenuse. In the second one you have to find the longest side. Use the Pythagoras Theorem again. Want to give it a go?
anonymous
  • anonymous
Can you explain using images?
anonymous
  • anonymous
|dw:1333310923250:dw| The side indicated is the hypotenuse. It's the longest side on a right angled triangle and is always opposite the 90 degree angle indicated by the little box in the corner. So using the Pythagoras Theorem to find the length of the unknown side it looks like this.\[Hypotenuse^2 = Side1^2 +Side2^2\]
anonymous
  • anonymous
i meant for 6
anonymous
  • anonymous
Side1 and Side2 values don't matter as long as you have your hypotenuse value in the correct spot. Here's another example. |dw:1333311257087:dw| To find the length of x (hypotenuse) sub the numbers into the formula \[x^2 =Side1^2 + Side^2 \] We get \[x^2 = 4^2 + 3^2\] This equals \[x^2 = 25\]. Then \[x \sqrt{25}=\] So x = 5. Do you understand?
anonymous
  • anonymous
6 isn't right angled then is it?
anonymous
  • anonymous
can u explain using the figure i gave?
anonymous
  • anonymous
Ok, never mind my last question. Use the Pythagoras theorem again. \[x^2 = 18^2 + 12^2\] This equals \[x^2 = 468\]. Then \[\sqrt{468}\]=21.63. Look at your options for your answers. It's definitely not a or d. So the answer has to be either b or c. \[6\sqrt{5}\]=13.42. So that's not our answer. \[6\sqrt{13}\]= 21.63 so there's your answer. Do you understand how I did all that?
anonymous
  • anonymous
yea

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