anonymous
  • anonymous
Use the Racetrack Principle and the fact that sin 0 = 0 to show that sin x(less than or equal to) x for all x (greater than or equal to) 0.
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
what the monkey is the "racetrack principle"?
anonymous
  • anonymous
oh maybe that since the derivative of sine is cosine and cosine is bounded above by 1, then \[\frac{\sin(x)-\sin(0)}{x-0}\leq 1\] so \[\sin(x)\leq x\]
anonymous
  • anonymous
ok I get that... is that still correct after looking at this pic
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