anonymous
  • anonymous
Nobody can help me. This question is here like for 1 hour: Locus of points z: |z-2|-|z+2|>3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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experimentX
  • experimentX
x< -2
anonymous
  • anonymous
how you got that?
experimentX
  • experimentX
wait,

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experimentX
  • experimentX
it not 2, it's x<-3/2
anonymous
  • anonymous
but explain how you got it
experimentX
  • experimentX
hit and trial ,,, have to wait for theory
anonymous
  • anonymous
i don't have correct answer. And not making any test. Just studying...
experimentX
  • experimentX
|z-2|-|z+2| > |z|+|2|-|z+2| >|z|+|2|-|z|-|2| > 3 => 2|z| > 3 => z > 3/2 or -z < 3/2 case 1 doesn't work so case 2 ... hahah ... lol good night 3 am here
anonymous
  • anonymous
I get something like this: \[28x ^{2} -14x +81>36y ^{2}\]
experimentX
  • experimentX
have to sleep ... can we discuss tomorrow?
anonymous
  • anonymous
|z-2|>|z|+|2|? kk, goodnight
experimentX
  • experimentX
oops sorry mistake here => z > 3/2 (for positive z) or z < -3/2 (for negative z) good night
anonymous
  • anonymous
|z-2|>|z|-|2|
experimentX
  • experimentX
|z-2|>|z|+|2| wrong
anonymous
  • anonymous
z is complex number
experimentX
  • experimentX
Oo ,,, sorry .. wrong assumption. let's discuss tomorrow
anonymous
  • anonymous
kk, thx
.Sam.
  • .Sam.
|z-2|-|z+2|>3 |z-2|>3+|z+2| |x+yi-2|>3+|(x+yi)+2| |(x-2)^2+y^2|>3+|(x+2)^2+y^2| x^2-4x+4+y^2>3+(x^2+4x+4)+y^2 -4x+4>4x+7 -8x>3 x<3/8
anonymous
  • anonymous
|(x-2)^2+y^2|>3+|(x+2)^2+y^2| ?? should't be square root?
experimentX
  • experimentX
yeah sqrt is missing ..
experimentX
  • experimentX
let wolf do the calc http://www.wolframalpha.com/input/?i=%28%28x-2%29%5E2%2By%5E2%29%5E%281%2F2%29%3E+3%2B%28%28x%2B2%29%5E2%2By%5E2%29%5E%281%2F2%29
anonymous
  • anonymous
I can come to this expression: \[14x(x-1/2)>9(y^{2}-9/4)\] anybody recognize what's that??
.Sam.
  • .Sam.
whoops forgot the square root \[\sqrt{(x-2)^2+y^2}>\sqrt{(x+2)^2+y^2}+3\]
anonymous
  • anonymous
but then yout result is wrong
.Sam.
  • .Sam.
you just need to sqrt both sides then the \[x<-\frac{3}{2} \]
anonymous
  • anonymous
\[(x-2)^{2}+y ^{2}>(x+2)^{2}+y ^{2} +6\sqrt{(x+2)^{2}+y ^{2}} +9\]
anonymous
  • anonymous
can you show me how you got that? @.Sam.
.Sam.
  • .Sam.
which one?
anonymous
  • anonymous
x<-3/2
perl
  • perl
the one that was before the last ?

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