anonymous
  • anonymous
Express the following as a single logarithm. ln(8+x^5)+(1/2)lnx−ln(cosx)
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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AccessDenied
  • AccessDenied
You'd just use some simple logarithm properties; even though the contents may be complicated, they still apply in the same way a*ln(b) = ln(a^b) ln(a) + ln(b) = ln(ab) ln(a) - ln(b) = ln(a/b)
AccessDenied
  • AccessDenied
first property should be = ln(b^a) *
anonymous
  • anonymous
Originally this is what I had came up with: \[(8+x^5)*(x^{1/2})/(\cos x)*\ln\]

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AccessDenied
  • AccessDenied
other than the fact that the ln is out of place (the function 'ln' should contain that expression as an argument, not be multiplied to it), it looks correct to me. \( \large{ ln(\frac{(8+x^5)(x^{1/2})}{cos(x)}) }\)
AccessDenied
  • AccessDenied
you could probably simplify it too by mutliplying the x^(1/2) through and changing 1/cos(x) to sec(x) and multiplying that through as well.

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