anonymous
  • anonymous
How do I prove this an Identiy?: ((cos(a+b))/(cosa +sinb))=((cosa - sinb)/(cos(b-a))) Please help. any help would be appreciated
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
what is cos(a+b) ? and almost the same, what is cos(b-a) ?
anonymous
  • anonymous
cos(a+b)= (cosa)(cosb)-(sina)(sinb) cos(b-a)= (cosb)(cosa)+(sinb)(sina)
anonymous
  • anonymous
my proof isnt going where I thought it would, sorry

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anonymous
  • anonymous
thanks for trying
anonymous
  • anonymous
please help
anonymous
  • anonymous
(cos(a)+sin(b))x(cos(a)-sin(b))=cos^2(a)-sin^2(b) and then use the cosxcosy=1/2 (cos(x-y)+cos(x+y)) identity to figure out what the other end comes out. I can't guarantee it to work, but I think you should give it a try.
anonymous
  • anonymous
I couldn't do it, but if you can simplify ((cos(a+b))/(cosa +sinb)) - ((cosa - sinb)/(cos(b-a))) down to 0, you will have your proof, just not in the right form. It is possible, but not for me (yet). Again, sorry I couldn't be more help.

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