anonymous
  • anonymous
g(x) = |x| Is that a one-one function? Why?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Directrix
  • Directrix
In a 1<-->1 function, for every x, there is a unique y. And, for every y, there is a unique x. In g(x) = |x|, 1 is mapped to 1 and -1 is also mapped to 1. On the flip side, a y of 1 is mapped to x values both 1 and -1.
anonymous
  • anonymous
so since -1 and 1 both become 1 that means it isnt a 1-1 function?
Directrix
  • Directrix
Yes, both of these conditions are required: In g(x) = |x|, 1 is mapped to 1 and -1 is also mapped to 1. On the flip side, a y of 1 is mapped to x values both 1 and -1. One-to-One Function A function for which every element of the range of the function corresponds to exactly one element of the domain. One-to-one is often written 1-1. Note: y = f(x) is a function if it passes the vertical line test. It is a 1-1 function if it passes both the vertical line test and the horizontal line test. http://www.mathwords.com/o/one_to_one_function.htm

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
many thanks man!

Looking for something else?

Not the answer you are looking for? Search for more explanations.