anonymous
  • anonymous
In a given solution, you initially had 5mL of 0.1M MgCl2 in a test tube, then you mixed this with 5mL of 1M NH3 solution. (No reaction from shaking). Then, 1g of NH4Cl was added to this, and what was observed was this solid falling to the surface of the solution and slowly dissolving away.
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
In a given solution, you initially had 5mL of 0.1M MgCl2 in a test tube, then you mixed this with 5mL of 1M NH3 solution. (No reaction from shaking). Then, 1g of NH4Cl was added to this, and what was observed was this solid falling to the surface of the solution and slowly dissolving away. =============================================================================== Is there no reaction that occurred after the addition of NH4Cl? The question asks: Explain your observation with respect to the equilibrium reactions that exist in this test tube. The only equilibrium reaction(s) that I can think of from this is NH3 + H2O <=> NH4+ + H3O+, and NH4+ + H2O <=> NH3 + H3O+. I checked the solubility for MgCl2 twice in the textbook and I concluded (from not seeing it anywhere in the solubility constant tables) that it is soluble. Is there any other equilibrium reactions that can be happening be present?

Looking for something else?

Not the answer you are looking for? Search for more explanations.