anonymous
  • anonymous
integral x^3/(x^2-2) dx I did u sub and got (x^2-2)/2 + ln(x^2-2) + C but wolfram alpha says it's x^2/2 + ln(x^2-2) + C did I do something wrong? does u sub here don't work?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Zarkon
  • Zarkon
those answers are the same
anonymous
  • anonymous
how? I can see you could separate the fraction for the second one but where does the constant -2/2 go?
Zarkon
  • Zarkon
into the other constant

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anonymous
  • anonymous
wouldn't that make the two constant different? +C and +C-1?
Zarkon
  • Zarkon
\[(x^2-2)/2 +\ln(x^2-2) + C\] \[=x^2/2 +\ln(x^2-2) + C-1\] \[=x^2/2 +\ln(x^2-2) + C_2\]
anonymous
  • anonymous
oh so because we don't know the value of original constant, we can assume any changes in the constant would not change the function?
Zarkon
  • Zarkon
It is not that we don't know the original constant...the antiderivative of a function \(f\) is a Function \(F\) such that \(F'=f\) both functions above satisfy this.
anonymous
  • anonymous
oh I think I see now thanks :)

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