anonymous
  • anonymous
Which is the extraneous solution of (pic about to be posted)? –5 –3 3 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
perl
  • perl
what is draco, and who is megan and who luv colin
perl
  • perl
square both sides

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anonymous
  • anonymous
ok
Directrix
  • Directrix
-x = √ (2x + 15) (-x)^2 = ( √ (2x + 15) ) ^2 x^2 = 2x + 15 x^2 - 2x - 15 = 0 (x - 5) ( x + 3) = 0 Zero Product Property x = 5 or x = -3 5 is the extraneous root because if 5 is substituted into the original equation: -5 = √ (2(-5) + 15) Immediately, you see that the square root cannot equal a negative number. These "extra" roots that are not true solutions of the original radical equation are called extraneous roots and are rejected as answers.

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