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gr12

what angles are coterminal with 160 degrees

  • 2 years ago
  • 2 years ago

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  1. gr12
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    @mertsj can u help me

    • 2 years ago
  2. gr12
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    anyone....?

    • 2 years ago
  3. jim_thompson5910
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    Anything coterminal to 160 degrees will be separated by 360 degrees. In other words, simply add/subtract 360 to/from 160 to get a new coterminal angle So one coterminal angle is 160 + 360 = 520 degrees

    • 2 years ago
  4. gr12
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    so would one be 20?

    • 2 years ago
  5. jim_thompson5910
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    another coterminal angle would be 160 - 360 = -200 degrees

    • 2 years ago
  6. gr12
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    thts not one of the options given to me. the options are : 20, 520 and -160, 200, and -200,-560, and 520, 700

    • 2 years ago
  7. ezhyl_marie
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    Coterminal angles Ac to angle A may be obtained by adding or subtracting k*360 degrees or k* (2 Pi). Hence Ac = A + k*360o if A is given in degrees. or Ac = A + k*(2 PI) if A is given in radians. where k is any negative or positive integer.

    • 2 years ago
  8. jim_thompson5910
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    sorry was delayed a bit Notice how -200 is one of our coterminal angles So if we subtract another 360 from that, we get -200 - 360 = -560 So the answer is choice C

    • 2 years ago
  9. ezhyl_marie
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    Find a positive and a negative angle coterminal with a 160° angle. 160° – 360° = –200° 160° + 360° = 520° A –200° angle and a 520° angle are co terminal with a 160° angle.

    • 2 years ago
  10. gr12
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    can u help me out with a couple more pleaseee?

    • 2 years ago
  11. gr12
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    its a different question, but its on trig

    • 2 years ago
  12. gr12
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    |dw:1333325937380:dw|

    • 2 years ago
  13. gr12
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    what is the depth of the water at 8:32 am

    • 2 years ago
  14. jim_thompson5910
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    I'm assuming that x = number of hours after 12:00 am?

    • 2 years ago
  15. gr12
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    t is the hours during a certain day

    • 2 years ago
  16. gr12
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    i mean x

    • 2 years ago
  17. jim_thompson5910
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    y = 2.5*sin(2pi*(x-4)/12.4) + 1.6 y = 2.5*sin(2pi*(8.533-4)/12.4) + 1.6 y = 2.5*sin(2pi*(4.533)/12.4) + 1.6 y = 2.5*sin(2pi*0.3655645) + 1.6 y = 2.5*sin(2(3.14159)*0.3655645) + 1.6 y = 2.5*sin(2*1.14845378) + 1.6 y = 2.5*sin(2.29690756) + 1.6 y = 2.5*0.74776206 + 1.6 y = 1.86940515 + 1.6 y = 3.46940515 So the water depth at 8:32 am is roughly 3.46940515

    • 2 years ago
  18. gr12
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    P( \[\sqrt{3}/2\], -1/2, and Q (-1/\[\sqrt{2}\], 1/\[\sqrt{2}\]

    • 2 years ago
  19. gr12
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    can u help me with 1 moree

    • 2 years ago
  20. jim_thompson5910
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    sure

    • 2 years ago
  21. gr12
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    p and q are 2 points on a unit circle. if an object rotates counterclock wise, from point p to point q, then through what angle in degrees has it rotated?

    • 2 years ago
  22. jim_thompson5910
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    Notice that cos(-pi/6) = sqrt(3)/2 and sin(-pi/6) = -1/2 and cos(5pi/4) = -1/sqrt(2) and sin(5pi/4) = 1/sqrt(2) So the two angles in question are: -pi/6 and 5pi/4 The difference between these angles are: 5pi/4 - (-pi/6) = 17pi/12 Therefore, the answer is 17pi/12

    • 2 years ago
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