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anonymous
 4 years ago
find d/dx of f^(1) (x)
anonymous
 4 years ago
find d/dx of f^(1) (x)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is the value of x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is f(x) = x/x + 1? or is f^1(x)= x/x +1?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well in any case, use the quotient rule where if you a function h defined as f/g then d/dx h = (f' * g  f * g') / g^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0..............x f(x) =  ..........x + 1 ........x y =  ......x + 1 ........y x =  ......y + 1 x(y + 1) = y xy + x = y xy  y =  x y(x  1) =  x ...........x y =   .........x  1 .................x f⁻¹(x) =   answer// ................x  1 bye..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got dat but it wasn't d ans

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to use the quotient rule next: x = f, x+1 = g d/dx x/x+1 = [1(x+1)  x(1)]/(x+1)^2 1/(x+1)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i got it now but it wasnt ur ans funinabox it was 1/(1x)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then you typed the problem wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then the answer is wrong 1/(1+x)^2 is the correct answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i know what's up f(x) = x/x + 1 it's not f^1(x) = x/x + 1 as was stated that way, when you do find the inverse, you get x/1x, which would give you the derivative you posted.
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