anonymous
  • anonymous
find d/dx of f^(-1) (x)
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
what is the value of x?
anonymous
  • anonymous
x/x + 1
anonymous
  • anonymous
is f(x) = x/x + 1? or is f^-1(x)= x/x +1?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
d 2
anonymous
  • anonymous
f^(-1) x = x/x+1
anonymous
  • anonymous
well in any case, use the quotient rule where if you a function h defined as f/g then d/dx h = (f' * g - f * g') / g^2
anonymous
  • anonymous
..............x f(x) = ------------- ..........x + 1 ........x y = -------- ......x + 1 ........y x = -------- ......y + 1 x(y + 1) = y xy + x = y xy - y = - x y(x - 1) = - x ...........x y = - --------- .........x - 1 .................x f⁻¹(x) = - ----------- answer// ................x - 1 bye..
anonymous
  • anonymous
nope
anonymous
  • anonymous
i got dat but it wasn't d ans
anonymous
  • anonymous
you need to use the quotient rule next: x = f, x+1 = g d/dx x/x+1 = [1(x+1) - x(1)]/(x+1)^2 1/(x+1)^2
anonymous
  • anonymous
yeah i got it now but it wasnt ur ans funinabox it was 1/(1-x)^2
anonymous
  • anonymous
thank u all
anonymous
  • anonymous
then you typed the problem wrong
anonymous
  • anonymous
no it was correct
anonymous
  • anonymous
then the answer is wrong 1/(1+x)^2 is the correct answer.
anonymous
  • anonymous
but i got the marks
anonymous
  • anonymous
i think i know what's up f(x) = x/x + 1 it's not f^-1(x) = x/x + 1 as was stated that way, when you do find the inverse, you get x/1-x, which would give you the derivative you posted.

Looking for something else?

Not the answer you are looking for? Search for more explanations.