anonymous
  • anonymous
Please Solve: (-2+8i)/(-4+4i)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
expand? FOIL just like you would if they were real numbers, remembering that i^2=-1 8-8i-32i+32i^2=8-40i-32=-24-40i
anonymous
  • anonymous
But dividing wouldnt it be less in fraction?
anonymous
  • anonymous
oh i didnt see the division sign

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anonymous
  • anonymous
Then it would be... 1+4i/2 ???
.Sam.
  • .Sam.
\[\frac{-2+8i}{-4+4i}*\frac{-4-4i}{-4-4i}\]
anonymous
  • anonymous
multiply top and bottom by \[-4-4i\] because \[(a+bi)(a-bi)=a^2+b^2\] a real number
anonymous
  • anonymous
mhm
anonymous
  • anonymous
what .sam. said denominator will be \[4^2+4^2=32\] all the work is multiplying in the numerator
anonymous
  • anonymous
but the result would be 1+4i/2 ???

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