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calyne

  • 2 years ago

If f(x) + x^2 * f(x) = 10 and f(1)=2, find f'(1).

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  1. yash007
    • 2 years ago
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    check ur ques. again its wrong it does not satisfy for f(1)=2 in the main equation

  2. calyne
    • 2 years ago
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    well that's the friggen problem verbatim from the textbook

  3. calyne
    • 2 years ago
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    OH pellet

  4. calyne
    • 2 years ago
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    it's not sorry geez sorry it's f(x) + x^2 * f(x)^3 = 10 the second f(x) term is cubed

  5. AnimalAin
    • 2 years ago
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    Maybe rearrange the problem a bit....\[y+x^2y=10\implies y=\frac{10}{1+x^2}\]I don't think your problem meets the specified conditions.

  6. yash007
    • 2 years ago
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    is ur anwer 2/5??

  7. calyne
    • 2 years ago
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    it's -16/13 that's the answer in the book

  8. calyne
    • 2 years ago
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    animalain - it's y + (x^2)(y^3) = 10

  9. AnimalAin
    • 2 years ago
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    Yeah, I got that. Trying to figure out my strategy....

  10. yash007
    • 2 years ago
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    yeah its done

  11. calyne
    • 2 years ago
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    ...

  12. AnimalAin
    • 2 years ago
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    How did you do it?

  13. yash007
    • 2 years ago
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    differentiate it n then put x=1 in equation u'll get the result

  14. yash007
    • 2 years ago
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    is that done??

  15. AnimalAin
    • 2 years ago
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    \[y + (x^2)(y^3) = 10\implies y'+2xy^3+3x^2y^2y'=0\]\[\implies y'(1+3x^2y^2)=-2xy^3\implies y'=\frac{-2xy^3}{1+3x^2y^2}\]\[\implies y'(1)=\frac{-16}{13}\]Got it. Need to practice my calculus a little more....LOL

  16. yash007
    • 2 years ago
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    all the best..:)

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