A community for students.
Here's the question you clicked on:
 0 viewing
calyne
 3 years ago
If f(x) + x^2 * f(x) = 10 and f(1)=2, find f'(1).
calyne
 3 years ago
If f(x) + x^2 * f(x) = 10 and f(1)=2, find f'(1).

This Question is Closed

yash007
 3 years ago
Best ResponseYou've already chosen the best response.0check ur ques. again its wrong it does not satisfy for f(1)=2 in the main equation

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0well that's the friggen problem verbatim from the textbook

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0it's not sorry geez sorry it's f(x) + x^2 * f(x)^3 = 10 the second f(x) term is cubed

AnimalAin
 3 years ago
Best ResponseYou've already chosen the best response.0Maybe rearrange the problem a bit....\[y+x^2y=10\implies y=\frac{10}{1+x^2}\]I don't think your problem meets the specified conditions.

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0it's 16/13 that's the answer in the book

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0animalain  it's y + (x^2)(y^3) = 10

AnimalAin
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, I got that. Trying to figure out my strategy....

yash007
 3 years ago
Best ResponseYou've already chosen the best response.0differentiate it n then put x=1 in equation u'll get the result

AnimalAin
 3 years ago
Best ResponseYou've already chosen the best response.0\[y + (x^2)(y^3) = 10\implies y'+2xy^3+3x^2y^2y'=0\]\[\implies y'(1+3x^2y^2)=2xy^3\implies y'=\frac{2xy^3}{1+3x^2y^2}\]\[\implies y'(1)=\frac{16}{13}\]Got it. Need to practice my calculus a little more....LOL
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.