anonymous
  • anonymous
A shipment of 12 microwave ovens contains 3 defective units. A vending company has ordered 4 of these units, and because all are packaged identically, the selection will be at random. What is the probability that at least 2 units are good?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
so usually 1/4 of the shipment is defective. so if we get 4 units. and 1/4 is bad. then we hav 4*1/4 is bad. which gives you a grand total of 1 bad one. so i think all the time you will have 2 good ones..
perl
  • perl
no you re wrong
lgbasallote
  • lgbasallote
are you classmates @perl & @EnchantixPixie ?

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anonymous
  • anonymous
No?
lgbasallote
  • lgbasallote
:okay:
Directrix
  • Directrix
Probability of a defective oven = 3/12 = 1/4 = .25 Probability of a non-defective oven = .75 P( 2 Defects) = C(4,2) * (.25)^2 * (.75)^2 = .2109 P( 3 Defects) = C(4,3) * (.25)^3 * (.75)^1 = .0469 P(4 Defects) = C(4,4) * (.25)^4 * (.75)^0 = .0039 Probability of at least 2 defective ovens = .2109 + .0469 + .0039 = .2617

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