A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2
anonymous
 4 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not that i tmatters anyway i'm just a little confused regarding the differentiation here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright give me a second to remember lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright i'll upload a picture on what to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and an example give me a sec

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like i got as far as [4x+4y*y']/[4x+4y*y'1] = 2x^2 + 2y^2  x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actualy i can't... i'll just type it out what my book says GUIDELINES FOR IMPLICIT DIFFERENTIATION 1. Differentiat both sides of the equatio with respects to x 2. collect al terms involve dy/dx on the left side of the equation and move all others to right 3.factor dy/dx out of the left side of the equation 4.solve for dy/dx by dividing both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0right righ tok so and

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what do i do from what i have am i good so far

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me get a piece of paper lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ama differentiate for u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so is coco checking if your differentiation is right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one question. just verifying... for the secon part, everyting is raised to teh 2nd power?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0umm. i suck @ algebra... and i think i am going to mess up if i do this. but, i am still going to go ahead and square all that. can someone then tell me if i was right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i got completely something else than he did

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the second is a chain and the first is just regular

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got 2x+2yy'=2(4x+4yy'1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you do implicit differentiation, then don't you do (for example, the first part): 2xdx+2ydy... then get all teh dx's and dy's on one side and divide so that dy/dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahh... i get it.. am so stupid! i was wondering where you got the chain rule from

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then you can pull out y'

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it's\[\frac{6x2}{6y}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the  is outside parenthesis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's been a while though lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0blah wait i messed up lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let me do this all over agani

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesn't help that i'm also trying to help two people

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, sorry guys but i am lost lol. but i wanna know how it's done. so outkast, once you did the chain rule, did you multiply or what?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my chain rule was messed up lol it should be \[2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes that's what i got

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'd say to combine the right side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's going to be ugly hahah

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dive 2xdx + 2ydy with 4xdx+4ydy...?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think you'd have to combine the right side which is a pain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hey, do you know is there anyway i can like mark this question so that i can come back and look @ it 2morrow?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no seriously?! ouch... calyne, your proff/teacher must be coldhearted to give you such a question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0um i think it should still be in the top left forner under notifications

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's not that bad tho

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2x+2yy'=16x^3+16y^3y'+16x^2yy'+16y^2x12x^24y^28xyy'+2x\] \[2yy'=16x^3+16^3y'+16x^2yy'+16y^2x12x^24y^28xyy'\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you get what me and coco got about my last when you used the chain rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you use the chain rule yeah du^2/du * du/dx first thing overall ik

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what you multiply that whole thing by dy/dx too

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so whta did you get after you take dy/dx of both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what did you get damn

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0using the chain rule i got 2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry i got 2x+2yy' = 2(2x^2+2y^2x) (4x + 4yy'  1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0alright so if you combine the terms on the right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is what i did ... what did you do after

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried a bunch of different stuff what was your final answer i'll tell you if it's correct nah flutter that the answer is x+1/2. is that what you got. if not we're wasting time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i have no idea.. even wolfram alpha has omething like my end answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0unless your teacher is crazy and solved for like y lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait the answer to the differentiation is that or the tangent line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because if it's the tangent line my implicit differentiation may be correct
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.