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Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2
 2 years ago
 2 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2
 2 years ago
 2 years ago

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calyneBest ResponseYou've already chosen the best response.1
not that i tmatters anyway i'm just a little confused regarding the differentiation here
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
alright give me a second to remember lol
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
alright i'll upload a picture on what to do
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
and an example give me a sec
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
like i got as far as [4x+4y*y']/[4x+4y*y'1] = 2x^2 + 2y^2  x
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
actualy i can't... i'll just type it out what my book says GUIDELINES FOR IMPLICIT DIFFERENTIATION 1. Differentiat both sides of the equatio with respects to x 2. collect al terms involve dy/dx on the left side of the equation and move all others to right 3.factor dy/dx out of the left side of the equation 4.solve for dy/dx by dividing both sides
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
so what do i do from what i have am i good so far
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
let me get a piece of paper lol
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
ama differentiate for u
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
so is coco checking if your differentiation is right?
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
one question. just verifying... for the secon part, everyting is raised to teh 2nd power?
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
umm. i suck @ algebra... and i think i am going to mess up if i do this. but, i am still going to go ahead and square all that. can someone then tell me if i was right?
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
yeah i got completely something else than he did
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
the second is a chain and the first is just regular
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
i got 2x+2yy'=2(4x+4yy'1)
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
=2x+2yy'= 8x+8yy'2
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
if you do implicit differentiation, then don't you do (for example, the first part): 2xdx+2ydy... then get all teh dx's and dy's on one side and divide so that dy/dx
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
ahh... i get it.. am so stupid! i was wondering where you got the chain rule from
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
then you can pull out y'
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
i think it's\[\frac{6x2}{6y}\]
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
the  is outside parenthesis
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
it's been a while though lol
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
blah wait i messed up lol
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
let me do this all over agani
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
it doesn't help that i'm also trying to help two people
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
ok, sorry guys but i am lost lol. but i wanna know how it's done. so outkast, once you did the chain rule, did you multiply or what?
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
my chain rule was messed up lol it should be \[2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)\]
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
yes that's what i got
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
then what did you do
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
i'd say to combine the right side
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
it's going to be ugly hahah
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
dive 2xdx + 2ydy with 4xdx+4ydy...?
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
i think you'd have to combine the right side which is a pain
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
Hey, do you know is there anyway i can like mark this question so that i can come back and look @ it 2morrow?
 2 years ago

cococupcoffeeBest ResponseYou've already chosen the best response.0
no seriously?! ouch... calyne, your proff/teacher must be coldhearted to give you such a question.
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
um i think it should still be in the top left forner under notifications
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
it's not that bad tho
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
\[2x+2yy'=16x^3+16y^3y'+16x^2yy'+16y^2x12x^24y^28xyy'+2x\] \[2yy'=16x^3+16^3y'+16x^2yy'+16y^2x12x^24y^28xyy'\]
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
did you get what me and coco got about my last when you used the chain rule
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
you use the chain rule yeah du^2/du * du/dx first thing overall ik
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
what you multiply that whole thing by dy/dx too
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
so whta did you get after you take dy/dx of both sides
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
using the chain rule i got 2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
sorry i got 2x+2yy' = 2(2x^2+2y^2x) (4x + 4yy'  1)
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
alright so if you combine the terms on the right
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
is what i did ... what did you do after
 2 years ago

calyneBest ResponseYou've already chosen the best response.1
i tried a bunch of different stuff what was your final answer i'll tell you if it's correct nah flutter that the answer is x+1/2. is that what you got. if not we're wasting time.
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
yeah i have no idea.. even wolfram alpha has omething like my end answer
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
unless your teacher is crazy and solved for like y lol
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
wait the answer to the differentiation is that or the tangent line
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
because if it's the tangent line my implicit differentiation may be correct
 2 years ago
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