anonymous
  • anonymous
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2 - x)^2
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
... @ (0,1/2)
anonymous
  • anonymous
not that i tmatters anyway i'm just a little confused regarding the differentiation here
anonymous
  • anonymous
alright give me a second to remember lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
alright i'll upload a picture on what to do
anonymous
  • anonymous
and an example give me a sec
anonymous
  • anonymous
cool thanks
anonymous
  • anonymous
like i got as far as [4x+4y*y']/[4x+4y*y'-1] = 2x^2 + 2y^2 - x
anonymous
  • anonymous
actualy i can't... i'll just type it out what my book says GUIDELINES FOR IMPLICIT DIFFERENTIATION 1. Differentiat both sides of the equatio with respects to x 2. collect al terms involve dy/dx on the left side of the equation and move all others to right 3.factor dy/dx out of the left side of the equation 4.solve for dy/dx by dividing both sides
anonymous
  • anonymous
by factor
anonymous
  • anonymous
right righ tok so and
anonymous
  • anonymous
so what do i do from what i have am i good so far
anonymous
  • anonymous
let me get a piece of paper lol
anonymous
  • anonymous
ama differentiate for u
anonymous
  • anonymous
thanks k cool coco
anonymous
  • anonymous
love it
anonymous
  • anonymous
so is coco checking if your differentiation is right?
anonymous
  • anonymous
one question. just verifying... for the secon part, everyting is raised to teh 2nd power?
anonymous
  • anonymous
i'm guessing
anonymous
  • anonymous
oh, ok
anonymous
  • anonymous
yes
anonymous
  • anonymous
ouch
anonymous
  • anonymous
umm. i suck @ algebra... and i think i am going to mess up if i do this. but, i am still going to go ahead and square all that. can someone then tell me if i was right?
anonymous
  • anonymous
yeah i got completely something else than he did
anonymous
  • anonymous
the second is a chain and the first is just regular
anonymous
  • anonymous
i got 2x+2yy'=2(4x+4yy'-1)
anonymous
  • anonymous
=2x+2yy'= 8x+8yy'-2
anonymous
  • anonymous
if you do implicit differentiation, then don't you do (for example, the first part): 2xdx+2ydy... then get all teh dx's and dy's on one side and divide so that dy/dx
anonymous
  • anonymous
yes
anonymous
  • anonymous
\[2yy'-8yy'=6x-2\]
anonymous
  • anonymous
ahh... i get it.. am so stupid! i was wondering where you got the chain rule from
anonymous
  • anonymous
yep
anonymous
  • anonymous
then you can pull out y'
anonymous
  • anonymous
i think it's\[\frac{-6x-2}{6y}\]
anonymous
  • anonymous
the - is outside parenthesis
anonymous
  • anonymous
\[-(6x-2)/6y\]
anonymous
  • anonymous
it's been a while though lol
anonymous
  • anonymous
blah wait i messed up lol
anonymous
  • anonymous
let me do this all over agani
anonymous
  • anonymous
i forgot something
anonymous
  • anonymous
it doesn't help that i'm also trying to help two people
anonymous
  • anonymous
ok, sorry guys but i am lost lol. but i wanna know how it's done. so outkast, once you did the chain rule, did you multiply or what?
anonymous
  • anonymous
my chain rule was messed up lol it should be \[2x+2yy'=2(2x^2+2y^2-x)(4x+4yy'-1)\]
anonymous
  • anonymous
yes that's what i got
anonymous
  • anonymous
then what did you do
anonymous
  • anonymous
i'd say to combine the right side
anonymous
  • anonymous
it's going to be ugly hahah
anonymous
  • anonymous
dive 2xdx + 2ydy with 4xdx+4ydy...?
anonymous
  • anonymous
divide*
anonymous
  • anonymous
i think you'd have to combine the right side which is a pain
anonymous
  • anonymous
Hey, do you know is there anyway i can like mark this question so that i can come back and look @ it 2morrow?
anonymous
  • anonymous
no seriously?! ouch... calyne, your proff/teacher must be coldhearted to give you such a question.
anonymous
  • anonymous
um i think it should still be in the top left forner under notifications
anonymous
  • anonymous
it's not that bad tho
anonymous
  • anonymous
Oh, ok. thanks!
anonymous
  • anonymous
\[2x+2yy'=16x^3+16y^3y'+16x^2yy'+16y^2x-12x^2-4y^2-8xyy'+2x\] \[2yy'=16x^3+16^3y'+16x^2yy'+16y^2x-12x^2-4y^2-8xyy'\]
anonymous
  • anonymous
...
anonymous
  • anonymous
did you get what me and coco got about my last when you used the chain rule
anonymous
  • anonymous
what
anonymous
  • anonymous
you use the chain rule yeah du^2/du * du/dx first thing overall ik
anonymous
  • anonymous
what you multiply that whole thing by dy/dx too
anonymous
  • anonymous
so whta did you get after you take dy/dx of both sides
anonymous
  • anonymous
what did you get damn
anonymous
  • anonymous
using the chain rule i got 2x+2yy'=2(2x^2+2y^2-x)(4x+4yy'-1)
anonymous
  • anonymous
sorry i got 2x+2yy' = 2(2x^2+2y^2-x) (4x + 4yy' - 1)
anonymous
  • anonymous
yeahhhh
anonymous
  • anonymous
alright so if you combine the terms on the right
anonymous
  • anonymous
is what i did ... what did you do after
anonymous
  • anonymous
idk that's gay
anonymous
  • anonymous
i tried a bunch of different stuff what was your final answer i'll tell you if it's correct nah flutter that the answer is x+1/2. is that what you got. if not we're wasting time.
anonymous
  • anonymous
not done yet haha
anonymous
  • anonymous
yeah i have no idea.. even wolfram alpha has omething like my end answer
anonymous
  • anonymous
unless your teacher is crazy and solved for like y lol
anonymous
  • anonymous
wait the answer to the differentiation is that or the tangent line
anonymous
  • anonymous
because if it's the tangent line my implicit differentiation may be correct

Looking for something else?

Not the answer you are looking for? Search for more explanations.