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calyne
 3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2
calyne
 3 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the curve at the given point: x^2 + y^2 = (2x^2 + 2y^2  x)^2

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calyne
 3 years ago
Best ResponseYou've already chosen the best response.1not that i tmatters anyway i'm just a little confused regarding the differentiation here

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0alright give me a second to remember lol

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0alright i'll upload a picture on what to do

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0and an example give me a sec

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1like i got as far as [4x+4y*y']/[4x+4y*y'1] = 2x^2 + 2y^2  x

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0actualy i can't... i'll just type it out what my book says GUIDELINES FOR IMPLICIT DIFFERENTIATION 1. Differentiat both sides of the equatio with respects to x 2. collect al terms involve dy/dx on the left side of the equation and move all others to right 3.factor dy/dx out of the left side of the equation 4.solve for dy/dx by dividing both sides

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1so what do i do from what i have am i good so far

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0let me get a piece of paper lol

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0ama differentiate for u

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0so is coco checking if your differentiation is right?

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0one question. just verifying... for the secon part, everyting is raised to teh 2nd power?

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0umm. i suck @ algebra... and i think i am going to mess up if i do this. but, i am still going to go ahead and square all that. can someone then tell me if i was right?

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i got completely something else than he did

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0the second is a chain and the first is just regular

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0i got 2x+2yy'=2(4x+4yy'1)

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0=2x+2yy'= 8x+8yy'2

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0if you do implicit differentiation, then don't you do (for example, the first part): 2xdx+2ydy... then get all teh dx's and dy's on one side and divide so that dy/dx

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0ahh... i get it.. am so stupid! i was wondering where you got the chain rule from

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0then you can pull out y'

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0i think it's\[\frac{6x2}{6y}\]

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0the  is outside parenthesis

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0it's been a while though lol

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0blah wait i messed up lol

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0let me do this all over agani

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0it doesn't help that i'm also trying to help two people

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0ok, sorry guys but i am lost lol. but i wanna know how it's done. so outkast, once you did the chain rule, did you multiply or what?

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0my chain rule was messed up lol it should be \[2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)\]

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0yes that's what i got

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0then what did you do

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0i'd say to combine the right side

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0it's going to be ugly hahah

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0dive 2xdx + 2ydy with 4xdx+4ydy...?

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0i think you'd have to combine the right side which is a pain

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0Hey, do you know is there anyway i can like mark this question so that i can come back and look @ it 2morrow?

cococupcoffee
 3 years ago
Best ResponseYou've already chosen the best response.0no seriously?! ouch... calyne, your proff/teacher must be coldhearted to give you such a question.

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0um i think it should still be in the top left forner under notifications

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0it's not that bad tho

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0\[2x+2yy'=16x^3+16y^3y'+16x^2yy'+16y^2x12x^24y^28xyy'+2x\] \[2yy'=16x^3+16^3y'+16x^2yy'+16y^2x12x^24y^28xyy'\]

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0did you get what me and coco got about my last when you used the chain rule

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1you use the chain rule yeah du^2/du * du/dx first thing overall ik

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1what you multiply that whole thing by dy/dx too

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0so whta did you get after you take dy/dx of both sides

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0using the chain rule i got 2x+2yy'=2(2x^2+2y^2x)(4x+4yy'1)

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1sorry i got 2x+2yy' = 2(2x^2+2y^2x) (4x + 4yy'  1)

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0alright so if you combine the terms on the right

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0is what i did ... what did you do after

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1i tried a bunch of different stuff what was your final answer i'll tell you if it's correct nah flutter that the answer is x+1/2. is that what you got. if not we're wasting time.

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i have no idea.. even wolfram alpha has omething like my end answer

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0unless your teacher is crazy and solved for like y lol

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0wait the answer to the differentiation is that or the tangent line

Outkast3r09
 3 years ago
Best ResponseYou've already chosen the best response.0because if it's the tangent line my implicit differentiation may be correct
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