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... @ (0,1/2)

not that i tmatters anyway i'm just a little confused regarding the differentiation here

alright give me a second to remember lol

alright i'll upload a picture on what to do

and an example give me a sec

cool thanks

like i got as far as [4x+4y*y']/[4x+4y*y'-1] = 2x^2 + 2y^2 - x

by factor

right righ tok so and

so what do i do from what i have am i good so far

let me get a piece of paper lol

ama differentiate for u

thanks k cool coco

love it

so is coco checking if your differentiation is right?

one question. just verifying... for the secon part, everyting is raised to teh 2nd power?

i'm guessing

oh, ok

yes

ouch

yeah i got completely something else than he did

the second is a chain and the first is just regular

i got 2x+2yy'=2(4x+4yy'-1)

=2x+2yy'= 8x+8yy'-2

yes

\[2yy'-8yy'=6x-2\]

ahh... i get it.. am so stupid! i was wondering where you got the chain rule from

yep

then you can pull out y'

i think it's\[\frac{-6x-2}{6y}\]

the - is outside parenthesis

\[-(6x-2)/6y\]

it's been a while though lol

blah wait i messed up lol

let me do this all over agani

i forgot something

it doesn't help that i'm also trying to help two people

my chain rule was messed up lol it should be
\[2x+2yy'=2(2x^2+2y^2-x)(4x+4yy'-1)\]

yes
that's what i got

then what did you do

i'd say to combine the right side

it's going to be ugly hahah

dive 2xdx + 2ydy with 4xdx+4ydy...?

divide*

i think you'd have to combine the right side which is a pain

no seriously?! ouch... calyne, your proff/teacher must be coldhearted to give you such a question.

um i think it should still be in the top left forner under notifications

it's not that bad tho

Oh, ok. thanks!

...

did you get what me and coco got about my last when you used the chain rule

what

you use the chain rule yeah du^2/du * du/dx first thing overall ik

what you multiply that whole thing by dy/dx too

so whta did you get after you take dy/dx of both sides

what did you get damn

using the chain rule i got
2x+2yy'=2(2x^2+2y^2-x)(4x+4yy'-1)

sorry i got 2x+2yy' = 2(2x^2+2y^2-x) (4x + 4yy' - 1)

yeahhhh

alright so if you combine the terms on the right

is what i did ... what did you do after

idk that's gay

not done yet haha

yeah i have no idea.. even wolfram alpha has omething like my end answer

unless your teacher is crazy and solved for like y lol

wait the answer to the differentiation is that or the tangent line

because if it's the tangent line my implicit differentiation may be correct