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try factoring out the numerator and the denominator..what factors would you get?
see if that denominator can be factored first. take out a 5...
yeah 5 so (x-3)/ 5(x^2 + x - 12) ?
seems x^2 + x -3 can be factored as well...try factoring it out..
im not sure how but would you take the x out? D:
no..you factor out binomials..
its a trinomial in the denominator
(x-3) -------------- 5 ( x-3)(x+4)
now see if you can cancel. (please give me medal. )
okay so 5(x +4)?
wait 1 / that?
yay it is thanks guys!
it says express this as single fractions in its simplest form : 1/x + 2/(x+4)
we need to find a common denominator first,
i simplified it and i got 3x + 4 but the answer is 3x +4 / (x(x+4)) :(
so we know that
the common denominator is x(x+4) , agreed?
ok so now we have to make each term have that denominator
we know that we can multiply the first fraction by (x+4)/(x+4) which is the same thing as multiplying by 1 (so its a legal operation)
and we can multiply the second term by x/x ,again the same thing as multiplying by 1. so its legal
1 (x+4) 2 ( x) -- * ---- + ---- * ---- x (x+4) (x+4) ( x)
its legal in the sense that multiplying by 1 does not change the number , we are only changing it's 'form' , to make it easier to manipulate or add
oh okay yep
collect like terms on the top, and you may or may not choose to expand the bottom by distributing. somtimes it is better to leave denominator factored
yep so 3x +4/ (x X x+4)
woo thanks :)