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umm ... must be less than 2500

those r five digit numbers..

I don't think this is possible, unless you count 00000 as a 5 digit number.

why do u think so?

i know the answer..21978 and 87912..but i am looking for the process

hm I stand corrected. haha

(Ax10000+Bx1000+Cx100+Dx10+E) × 4 = Ex10000+Dx1000+Cx100+Bx10+A

well, not so tough problem..

this is the longest reply i have typed in openstudy^^ :D

nice answer !!

thanx, @experimentX, at least u have honored my labor to type it :D

oh ...! i had bookmarked this problem for a while .. thanks to you!

it's solved now :D

yup.. i solved similar prob before.. 4 digit, 5 digit is a little more complicated..

@gingerkid101, this is possible except 00000 :D

what happened??