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sritama
Given two unmarked jugs, one which holds 7 liters, and another which holds 11 liters, an unlimited supply of water, and no need to conserve, how do you measure exactly 6 liters?
at lest you need 2 pairs of such jugs ...
experiment, that question by ravus was not meant to use binomial series, lol
how did you think of that? i am jealous
you can measure 18 by putting water in both glasses.
you can measure 4 litres .. but pouring 11 litres to 7 litres. now to measure 6, put water in both jars, the pour to 11 lit jar => 7 lit jar ==> throw remaining in 11 lit jar = 4 litre continue this 3 times .. you would throw 4x3 = 12 lit or 18 - 12 = 6
@perl you mean this question or that question??
fill up 11 jar, pour it into 7 jar. that leaves you with 4 in Eleven jar now spill out seven jar.
and after emptying the 7 jar??
sorry, this is easy, start over Fill up seven jar pour the seven jar into the empty eleven jar. Now again , fill up seven jar and pour it into eleven jar. That will leave you with 3 in the seven jar. spill out the eleven jar. Now pour the seven jar in with the 3 inside into the empty elevan jar.
sorry, this is easy, start over Fill up seven jar pour the seven jar into the empty eleven jar. Now again , fill up seven jar and pour it into eleven jar. That will leave you with 3 in the seven jar. spill out the eleven jar. Now pour the seven jar with the 3 inside into the empty elevan jar. Now fill up the empty seven jar. Pour the full 7 into the eleven jar. Now you have ten in the eleven jar. Now fill up seven jar , pour into the eleven jar until it reaches top. So you have 6 now in the seven jar.
the goal is to get ten in the eleven jar. once you have ten, you can pour the seven jar into the eleven jar, and it subtracts 1 making six
i dont understand experiments solution
what experiment answered, i think it cant b done..its the solution how to get 6 from 7 and 11..
measure 18, filter out 4, throw it --- 3 times 6 liters will remain