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yeah...

what is initial?

the amount of grass that the field had initially

yeah i figured out that.

so you set them equal to each other because you assumed they ate all the grass

I didn't assume, they said that they "cleared the field"

errr, that was given

so what exactly are you equating , what is your left side and right side

total grass grown = total grass eaten (over the days )

ok but thats 2 equations in 3 unknowns

the grass is growing while they are eating

grass growth must be some function of days

well you can subtract equation 1 from equation 2, that eliminates x the initial

by eliminating the initial i will find the relation between m and n

how did you get grass growth rate is 90 and 30 ?

nevermind

that was days

Yeah sritama I was actually just about to correct my equations to add the days on both sides.

yeah,i took the grass growth rate n/each day ... so it must b 90n and 30n

oh ok gingerkid 101

ginger can you redo your equation

i like your equation, its very logical :)

yeah thats a little odd, grass per cow per day

how does that come out in units, grass/ (cow/day) or

probably it means the amount of grass taken by each cow per day

grass/(cow * day) or grass/cow/day
it's all the same.

ok now its linear algebra, one moment

x + 30y - 3600j=0
x + 90y- 4320j=0

I get x = 3240 j
y = 12j
j = j

actually we know we want 16 , so we have another equation

x + 30y = 3600j
x + 90y = 4320j
x + 16 y = 16 i * j

how did you get 8 additional cows?

yeah,thats my question too

8 additional to 1/3 of 120. maybe I'm just talking out of my retricenow haha

I don't even know. meh, I never had to do anything like this and I took up to calc 3 haha

well this is a solid start

i got 12j = y , so 12 cows it takes to eat the grass grown in 1 day