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.Sam.Best ResponseYou've already chosen the best response.4
\[\huge 7.3^{x1}+53^{x+1}=0\]
 2 years ago

perlBest ResponseYou've already chosen the best response.0
is that 7*3^(x1) or (7.3)^(x1)
 2 years ago

lgbasalloteBest ResponseYou've already chosen the best response.0
do tell me..does this involve canceling 3^x1 the solution i thought had that..
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
\[3^x = \frac{15}{2}\] \[x = \log_3 \frac{15}2\]
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
@Ishaan94 that's true if the decimal was "dot" *
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
Oh, my bad... so it's \[(7.3)^{x1} + 53^{x+1}=0\]Hmm Now I feel stupid :/
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
campbell decimal point, 7.3 = 73/10
 2 years ago

perlBest ResponseYou've already chosen the best response.0
its an annoying problem. whats the bloody solution?
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
ln(a+b) is not the same as lna +lnb
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
You can't take log like that
 2 years ago

Ishaan94Best ResponseYou've already chosen the best response.0
I think 7.3 has something to do with 5, we should try to use 5
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
wolf's answer http://www.wolframalpha.com/input/?i=7.3%5E%28x1%29%2B53%5E%28x%2B1%29%3D0
 2 years ago

perlBest ResponseYou've already chosen the best response.0
why did he say this is easy problem
 2 years ago

karatechopperBest ResponseYou've already chosen the best response.0
hhe says its easy and im still stuck on first step, can i switch signs?
 2 years ago

karatechopperBest ResponseYou've already chosen the best response.0
i meant he, meaning sam
 2 years ago

perlBest ResponseYou've already chosen the best response.0
i think this could somehow become a quadratic, with the right substitution
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
i don't think general method we use would work
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
how do you solve this 2^x  x = 2
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
I think we could only use newtons method......
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
first we approximate an answer....
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
then use the newton's method to get a better aproximation
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
we continue this until we're satisfied
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
but we can't still get the exact though :(
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
currently the best way to solve is graphical method ... lol
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
the number 5 is irritating
 2 years ago

perlBest ResponseYou've already chosen the best response.0
i sent sam a message, he better respond .
 2 years ago

perlBest ResponseYou've already chosen the best response.0
what is classic about this problem anyway?
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
i assume that is \(7.3^{x1}\) and not \(7\cdot 3^{x1}\) so i have no ideas yet
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
must be something special about 7.3 that i do not see
 2 years ago

perlBest ResponseYou've already chosen the best response.0
can you guys tell me later, i gotta sleep
 2 years ago

perlBest ResponseYou've already chosen the best response.0
ok try this , let u = 3^(x+1)
 2 years ago

perlBest ResponseYou've already chosen the best response.0
i assume there is an exact solution, otherwise youve wasted my time
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
I can see that you guys think so hard, lol
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
Sad thing for you @perl There's no exact solution but approximation \[7.3^{x1}=3^{x+1}5\]
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
i knew that newtoms method of approximation yesterday..
 2 years ago

perlBest ResponseYou've already chosen the best response.0
it would be more interesting if there was exact solution , :(
 2 years ago

perlBest ResponseYou've already chosen the best response.0
i was confused since you said it was easy problem , rats
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
newton's method :D
 2 years ago

anonymoustwo44Best ResponseYou've already chosen the best response.0
newton's method :D
 2 years ago

perlBest ResponseYou've already chosen the best response.0
ok then how is it easy to approximate?
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
Its easy you don't even need to think, lol
 2 years ago

perlBest ResponseYou've already chosen the best response.0
it didnt look easy on wolfram
 2 years ago

perlBest ResponseYou've already chosen the best response.0
sam , so are you going to post the solution or not. cuz im getting really tired
 2 years ago

perlBest ResponseYou've already chosen the best response.0
you can use a calculator for this. is that your 'easy' solution ?
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
you have to graph it for 7.3^(x1) and 3^(x+1)5 pick some points
 2 years ago

perlBest ResponseYou've already chosen the best response.0
what program do you use to graph that?
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
its a tedious job though, but if you have a graphing calc, it will be fine
 2 years ago

perlBest ResponseYou've already chosen the best response.0
then why do you say its easy?
 2 years ago

perlBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=7.3^%28x1%29%2B53^%28x%2B1%29%3D0
 2 years ago

perlBest ResponseYou've already chosen the best response.0
what do you mean , pick some points? estimate
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Newtons Method i think..
 2 years ago

perlBest ResponseYou've already chosen the best response.0
i dont think so, its just approximation problem
 2 years ago

perlBest ResponseYou've already chosen the best response.0
anyways, the question seemed pretty ambiguous. i didnt know what they meant by 'easy'
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
lol, thats all? guessing?
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
you can use this program to graph https://www.desmos.com/calculator/c
 2 years ago

perlBest ResponseYou've already chosen the best response.0
then you do screen capture?
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
sigh..you can state your question as finding the approximation than 'solve for x'
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
@Mimi_x3 yes its a bit of disappointing, but I'll come up with a new question later :)
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
@perl no i dont screen cap on that software
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
lol, i wanted to see a solution..but there is no solution *sigh*
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
the solution is approximation ,lol
 2 years ago

.Sam.Best ResponseYou've already chosen the best response.4
Nevermind I'll come up a new one :)
 2 years ago

Mimi_x3Best ResponseYou've already chosen the best response.0
Alright, please state your question correctly next time.
 2 years ago

perlBest ResponseYou've already chosen the best response.0
I think there is a confusion, he copied the problem originally with multiplication 7*3^(x1)
 2 years ago

apoorvkBest ResponseYou've already chosen the best response.0
c'mon i got the approximate thing using 'jugaad' :/
 2 years ago
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