anonymous
  • anonymous
Find vectors perpendicular to both of the given vectors. (a) ---> (3i-2k) and 2k
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
do the same cross product: your vectors are (3,0,-2) and (0,0,2)
anonymous
  • anonymous
-6j
anonymous
  • anonymous
Oh, Ok.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
It says j is also a possiblity in my textbook?
anonymous
  • anonymous
ya, any j actualy
anonymous
  • anonymous
It just says, -6j or j are the answers.. how is j?
anonymous
  • anonymous
sry.. Only -6j this is what you get when cros multiply your vectors.
anonymous
  • anonymous
But it says j is also an answer...
anonymous
  • anonymous
(3,0,-2) and (0,0,2) (0,a,0).(3,0,-2) = 0 + 0 + 0 =0 (0,a,0).(0,0,2) = 0 + 0 + 0 = 0 So actualy any (0,a,0) vector will do. I said -6j, since that's the result of cross multiplication, but this vector is equal -6(0,1,0) no? so it's paralel .
anonymous
  • anonymous
any paralel vector to -6j will be also a solution. Ok?
anonymous
  • anonymous
hmmm. OK
anonymous
  • anonymous
if you dont get it, tell me i try to explain better
anonymous
  • anonymous
I understand. Don't worry :)
anonymous
  • anonymous
kk

Looking for something else?

Not the answer you are looking for? Search for more explanations.