## anonymous 4 years ago Find the horizontal asymptote of y=1/(x-2) -3

1. anonymous

y=-3

2. anonymous

thats nice, but how do i find it on my own?

3. anonymous

your function is a hyperbola. For it to have a horizontal asymptote,it means that if x goes to +- infinity y should aprouch some kind of value: so take the limit:$\lim_{x \rightarrow \infty} 1/(x-2) -3 = -3$ that's it

4. anonymous

so as x gets larger it pull 1/x-2 to 0

5. anonymous

yes

6. anonymous

leaving me -3

7. anonymous

right

8. anonymous

thanks a ton

9. anonymous

you wellcome