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ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0thats nice, but how do i find it on my own?

myko
 2 years ago
Best ResponseYou've already chosen the best response.1your function is a hyperbola. For it to have a horizontal asymptote,it means that if x goes to + infinity y should aprouch some kind of value: so take the limit:\[\lim_{x \rightarrow \infty} 1/(x2) 3 = 3\] that's it

ChrisV
 2 years ago
Best ResponseYou've already chosen the best response.0so as x gets larger it pull 1/x2 to 0
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