## ChrisV Group Title Find the horizontal asymptote of y=1/(x-2) -3 2 years ago 2 years ago

1. myko

y=-3

2. ChrisV

thats nice, but how do i find it on my own?

3. myko

your function is a hyperbola. For it to have a horizontal asymptote,it means that if x goes to +- infinity y should aprouch some kind of value: so take the limit:$\lim_{x \rightarrow \infty} 1/(x-2) -3 = -3$ that's it

4. ChrisV

so as x gets larger it pull 1/x-2 to 0

5. myko

yes

6. ChrisV

leaving me -3

7. myko

right

8. ChrisV

thanks a ton

9. myko

you wellcome