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Find the horizontal asymptote of y=1/(x-2) -3

Mathematics
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y=-3
thats nice, but how do i find it on my own?
your function is a hyperbola. For it to have a horizontal asymptote,it means that if x goes to +- infinity y should aprouch some kind of value: so take the limit:\[\lim_{x \rightarrow \infty} 1/(x-2) -3 = -3\] that's it

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Other answers:

so as x gets larger it pull 1/x-2 to 0
yes
leaving me -3
right
thanks a ton
you wellcome

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