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ChrisV Group Title

Find the horizontal asymptote of y=1/(x-2) -3

  • 2 years ago
  • 2 years ago

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  1. myko Group Title
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    y=-3

    • 2 years ago
  2. ChrisV Group Title
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    thats nice, but how do i find it on my own?

    • 2 years ago
  3. myko Group Title
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    your function is a hyperbola. For it to have a horizontal asymptote,it means that if x goes to +- infinity y should aprouch some kind of value: so take the limit:\[\lim_{x \rightarrow \infty} 1/(x-2) -3 = -3\] that's it

    • 2 years ago
  4. ChrisV Group Title
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    so as x gets larger it pull 1/x-2 to 0

    • 2 years ago
  5. myko Group Title
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    yes

    • 2 years ago
  6. ChrisV Group Title
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    leaving me -3

    • 2 years ago
  7. myko Group Title
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    right

    • 2 years ago
  8. ChrisV Group Title
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    thanks a ton

    • 2 years ago
  9. myko Group Title
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    you wellcome

    • 2 years ago
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