pythagoras123
  • pythagoras123
Find the smallest number such that i) it leaves a remainder 2 when divided by 3; ii) it leaves a remainder 3 when divided by 5; iii) it leaves a remainder 5 when divided by 7.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
i)5 ii)8
anonymous
  • anonymous
iii.)12
pythagoras123
  • pythagoras123
The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

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More answers

anonymous
  • anonymous
ah ok
anonymous
  • anonymous
LCM of 5,8,12 is the answer
pythagoras123
  • pythagoras123
Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.
anonymous
  • anonymous
Sorry for that. I have made a mistake
hoblos
  • hoblos
68= 3*22 +2 = 5*13 +3 = 7*9 + 5

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