Find the smallest number such that i) it leaves a remainder 2 when divided by 3; ii) it leaves a remainder 3 when divided by 5; iii) it leaves a remainder 5 when divided by 7.

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Find the smallest number such that i) it leaves a remainder 2 when divided by 3; ii) it leaves a remainder 3 when divided by 5; iii) it leaves a remainder 5 when divided by 7.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i)5 ii)8
iii.)12
The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

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Other answers:

ah ok
LCM of 5,8,12 is the answer
Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.
Sorry for that. I have made a mistake
68= 3*22 +2 = 5*13 +3 = 7*9 + 5

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