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Find the smallest number such that i) it leaves a remainder 2 when divided by 3; ii) it leaves a remainder 3 when divided by 5; iii) it leaves a remainder 5 when divided by 7.

Mathematics
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i)5 ii)8
iii.)12
The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

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Other answers:

ah ok
LCM of 5,8,12 is the answer
Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.
Sorry for that. I have made a mistake
68= 3*22 +2 = 5*13 +3 = 7*9 + 5

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