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pythagoras123

  • 4 years ago

Find the smallest number such that i) it leaves a remainder 2 when divided by 3; ii) it leaves a remainder 3 when divided by 5; iii) it leaves a remainder 5 when divided by 7.

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  1. anonymoustwo44
    • 4 years ago
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    i)5 ii)8

  2. anonymoustwo44
    • 4 years ago
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    iii.)12

  3. pythagoras123
    • 4 years ago
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    The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.

  4. anonymoustwo44
    • 4 years ago
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    ah ok

  5. CoCoTsoi
    • 4 years ago
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    LCM of 5,8,12 is the answer

  6. pythagoras123
    • 4 years ago
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    Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.

  7. CoCoTsoi
    • 4 years ago
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    Sorry for that. I have made a mistake

  8. hoblos
    • 4 years ago
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    68= 3*22 +2 = 5*13 +3 = 7*9 + 5

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