pythagoras123
Find the smallest number such that
i) it leaves a remainder 2 when divided by 3;
ii) it leaves a remainder 3 when divided by 5;
iii) it leaves a remainder 5 when divided by 7.
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anonymoustwo44
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i)5
ii)8
anonymoustwo44
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iii.)12
pythagoras123
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The question asks for a number satisfying all the 3 conditions, not 3 separate numbers fufiling each individual condition.
anonymoustwo44
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ah ok
CoCoTsoi
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LCM of 5,8,12 is the answer
pythagoras123
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Ermm, LCM of 5,8 and 12 is 120. 120 does not yield any remainder when divided by 3 or 5.
CoCoTsoi
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Sorry for that. I have made a mistake
hoblos
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68= 3*22 +2
= 5*13 +3
= 7*9 + 5