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I also have to find angle measures 2, 3, 4, 5, 6, 7, 8.
a straight line has angle measure 180° ... in your diagram arc BE is 180° so if BE is 180° and AE is 53° what is AB?
oh, so AB has to be =127?
so would angle 1 and 3 be the same?
are those parallel lines intersecting the same line?
but doesn't it have the little half circle that makes it congruent?
is anything else given besides those 3 angle measures?
no. I'm really confused, sorry.
I am too, don't see how to get any of the other angles but since it is circle P, the lengths of PE = PB = PD
um, how can I use that information for the questions? I don't think I have any parallel lines to work with.
ok, what do the angles of a triangle add up to? look at the triangle with base BD and you can get angle 3
180 per triangle right?
so, would it be 60?
and if DH is a tangent to circle P, then angle 4 is 90°
I don't think it is 60, but that's very very close
that looks better
soo wouldn't angle 2 be the measure of half that of angle four?
why would that be?
wait, nevermind I looked at it wrong.
forget all I just told you... I set it up wrong... arc AE does not tell you anything about the angles at point F sorry best bet is to delete all this or post it again
but the sum of the angles in a triange is 180 and opposite angles are the same and angles on a straight line are 180
angle BPE is 121
um okay, are all of the answers wrong? like, should I not use them to find the other angles?
right, except PDH is 90... property of a tangent, if that is one
BPE is isoscolese triangle so you know those 3 angles (angle BPE is 53+68)
add line PC and you know that BPC = 72, so you can find CPD and then triangle CPD is isoscolese so you can get those angles around D
well, that's about all I can do right now, hope it helped a little... but it has been 30 years since my last geometry class... EBC is 29.5° PDH is 90° if that is a tangent CDH is 54°