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yrivers36

  • 4 years ago

Is the sqrt of x = to x please?

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  1. Kreshnik
    • 4 years ago
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    \[\Large \sqrt[m]{a^n}=a^{\frac{n}{m}}\]

  2. Kreshnik
    • 4 years ago
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    \[\LARGE \sqrt{x}=x^{\frac12}\]

  3. yrivers36
    • 4 years ago
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    ok thank you. I forgot about that

  4. cwrw238
    • 4 years ago
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    no unless x = 1

  5. yrivers36
    • 4 years ago
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    so then if I have a problem like

  6. yrivers36
    • 4 years ago
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    |dw:1333375554625:dw|

  7. yrivers36
    • 4 years ago
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    that would not be

  8. yrivers36
    • 4 years ago
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    |dw:1333375584684:dw|

  9. Kreshnik
    • 4 years ago
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    |dw:1333375680517:dw|

  10. yrivers36
    • 4 years ago
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    ok so there i just break problem down before finding solution

  11. cwrw238
    • 4 years ago
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    |dw:1333375647733:dw|

  12. Kreshnik
    • 4 years ago
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    \[\LARGE \sqrt[2]{y^2}=y^{2/2}=y^1=y\] when we write \[\LARGE \sqrt y\] there's number two in square root, but we don't write it !

  13. yrivers36
    • 4 years ago
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    Ok thank you so much!!!!!!!!!!:)

  14. Kreshnik
    • 4 years ago
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    Glad to help :)

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