Solve the equation. Identify any extraneous solutions. see problem below

Solve the equation. Identify any extraneous solutions. see problem below

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\[x=\sqrt{x+30}\]

x^2= x+30
x^2-x-30=0
x=6,x=-5
and we put them into equation if they provide ,6 is ok,but -5 is not.

@yakkin09 so -5 is the extraneous

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