• anonymous
Can someone check if this is right: Need to prove that the sum of distinct nth roots of unity is equal 0. Looks to simple to me.... Proof: The different n rooths of unity can be seen like vertices of an n-gon inscribed in a unit circle of a complex plane. This n-gon is invariant under the rotation by 2Pi/n. In the complex numbers this rotation is expressed by multiplication by e^i(2Pi/n) So if the sum befor rotation is S, after rotation should be same. It means S = Se^i(2Pi/n) giving the only posibility that S =0
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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