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calyne

  • 4 years ago

Find y'' by implicit differentiation: 9x^2+y^2 = 9

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  1. robtobey
    • 4 years ago
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    http://www.youtube.com/watch?v=X0aw9-kXfY4

  2. Dockworker
    • 4 years ago
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    messed up the quotient rule...sigh

  3. calyne
    • 4 years ago
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    ...

  4. eigenschmeigen
    • 4 years ago
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    \[9x^2 +y^2 =9 \] \[\text{ } 18x +2y(dy/dx) = 0\] \[dy/dx=-(18x/2y)\] \[18 +2(dy/dx) + 2y(d^2y/dx^2) =0 \] \[d^2y/dx^2 = -(18 + 2(dy/dx))/2y\] now sub in dy/dx \[d^2y/dx^2 = -(18 - 2(18x/2y))/2y = 36(x - y)/(2y)^2\]

  5. eigenschmeigen
    • 4 years ago
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    no need for the quotient rule with that method

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